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1101321310153 is a prime number
BaseRepresentation
bin10000000001101011110…
…111011000111111001001
310220021200222100021111211
4100001223313120333021
5121021001223411103
62201535013453121
7142365524451511
oct20015367307711
93807628307454
101101321310153
11395082193959
1215953a3411a1
137cb14764abc
143b438b74841
151d9ab9a036d
hex1006bdd8fc9

1101321310153 has 2 divisors, whose sum is σ = 1101321310154. Its totient is φ = 1101321310152.

The previous prime is 1101321310099. The next prime is 1101321310163. The reversal of 1101321310153 is 3510131231011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 953644043209 + 147677266944 = 976547^2 + 384288^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1101321310153 is a prime.

It is not a weakly prime, because it can be changed into another prime (1101321310163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550660655076 + 550660655077.

It is an arithmetic number, because the mean of its divisors is an integer number (550660655077).

Almost surely, 21101321310153 is an apocalyptic number.

It is an amenable number.

1101321310153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101321310153 is an equidigital number, since it uses as much as digits as its factorization.

1101321310153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 270, while the sum is 22.

Adding to 1101321310153 its reverse (3510131231011), we get a palindrome (4611452541164).

The spelling of 1101321310153 in words is "one trillion, one hundred one billion, three hundred twenty-one million, three hundred ten thousand, one hundred fifty-three".