Base | Representation |
---|---|
bin | 10000000001101100011… |
… | …001101110111110110110 |
3 | 10220021201121021200021212 |
4 | 100001230121232332312 |
5 | 121021011030010032 |
6 | 2201535534441422 |
7 | 142365664126343 |
oct | 20015431567666 |
9 | 3807647250255 |
10 | 1101330313142 |
11 | 395087282a44 |
12 | 159541363272 |
13 | 7cb16597907 |
14 | 3b43a0397ca |
15 | 1d9ac67cbb2 |
hex | 1006c66efb6 |
1101330313142 has 4 divisors (see below), whose sum is σ = 1651995469716. Its totient is φ = 550665156570.
The previous prime is 1101330313133. The next prime is 1101330313219. The reversal of 1101330313142 is 2413130331011.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275332578284 + ... + 275332578287.
It is an arithmetic number, because the mean of its divisors is an integer number (412998867429).
Almost surely, 21101330313142 is an apocalyptic number.
1101330313142 is a deficient number, since it is larger than the sum of its proper divisors (550665156574).
1101330313142 is an equidigital number, since it uses as much as digits as its factorization.
1101330313142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 550665156573.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1101330313142 its reverse (2413130331011), we get a palindrome (3514460644153).
The spelling of 1101330313142 in words is "one trillion, one hundred one billion, three hundred thirty million, three hundred thirteen thousand, one hundred forty-two".
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