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11013312310 = 25711213293449
BaseRepresentation
bin10100100000111000…
…11100111100110110
31001102112111020021221
422100130130330312
5140023401443220
65020501300554
7536630416150
oct122034347466
931375436257
1011013312310
114741800600
12217440475a
131066908a60
14766977ad0
15446d1d9aa
hex29071cf36

11013312310 has 192 divisors, whose sum is σ = 27751248000. Its totient is φ = 3058513920.

The previous prime is 11013312307. The next prime is 11013312313. The reversal of 11013312310 is 1321331011.

11013312310 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (11013312307) and next prime (11013312313).

It is a super-2 number, since 2×110133123102 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11013312313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3191466 + ... + 3194914.

It is an arithmetic number, because the mean of its divisors is an integer number (144537750).

Almost surely, 211013312310 is an apocalyptic number.

11013312310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11013312310 is an abundant number, since it is smaller than the sum of its proper divisors (16737935690).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11013312310 is a wasteful number, since it uses less digits than its factorization.

11013312310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3527 (or 3516 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11013312310 its reverse (1321331011), we get a palindrome (12334643321).

It can be divided in two parts, 11013 and 312310, that added together give a palindrome (323323).

The spelling of 11013312310 in words is "eleven billion, thirteen million, three hundred twelve thousand, three hundred ten".