Base | Representation |
---|---|
bin | 10000000001101101001… |
… | …000000000011010011001 |
3 | 10220021202110002221112211 |
4 | 100001231020000122121 |
5 | 121021022131140121 |
6 | 2201541050435121 |
7 | 142366202210002 |
oct | 20015510003231 |
9 | 3807673087484 |
10 | 1101342443161 |
11 | 395093108454 |
12 | 159545432aa1 |
13 | 7cb18c53b3c |
14 | 3b43b8b61a9 |
15 | 1d9ad776ce1 |
hex | 1006d200699 |
1101342443161 has 2 divisors, whose sum is σ = 1101342443162. Its totient is φ = 1101342443160.
The previous prime is 1101342443119. The next prime is 1101342443191. The reversal of 1101342443161 is 1613442431011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1052255382025 + 49087061136 = 1025795^2 + 221556^2 .
It is a cyclic number.
It is not a de Polignac number, because 1101342443161 - 211 = 1101342441113 is a prime.
It is not a weakly prime, because it can be changed into another prime (1101342443101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550671221580 + 550671221581.
It is an arithmetic number, because the mean of its divisors is an integer number (550671221581).
Almost surely, 21101342443161 is an apocalyptic number.
It is an amenable number.
1101342443161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101342443161 is an equidigital number, since it uses as much as digits as its factorization.
1101342443161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 1101342443161 its reverse (1613442431011), we get a palindrome (2714784874172).
The spelling of 1101342443161 in words is "one trillion, one hundred one billion, three hundred forty-two million, four hundred forty-three thousand, one hundred sixty-one".
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