Base | Representation |
---|---|
bin | 1010000001000110101111… |
… | …0010000011111010110011 |
3 | 1102222221022212122002002011 |
4 | 2200101223302003322303 |
5 | 2420423341213313212 |
6 | 35231450522303351 |
7 | 2214512526654244 |
oct | 240215362037263 |
9 | 42887285562064 |
10 | 11014104432307 |
11 | 35670678a6739 |
12 | 129a735357b57 |
13 | 61b819568ca2 |
14 | 2a112a874ccb |
15 | 14177ea6a4a7 |
hex | a046bc83eb3 |
11014104432307 has 2 divisors, whose sum is σ = 11014104432308. Its totient is φ = 11014104432306.
The previous prime is 11014104432281. The next prime is 11014104432341. The reversal of 11014104432307 is 70323440141011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11014104432307 - 215 = 11014104399539 is a prime.
It is not a weakly prime, because it can be changed into another prime (11014104432347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507052216153 + 5507052216154.
It is an arithmetic number, because the mean of its divisors is an integer number (5507052216154).
Almost surely, 211014104432307 is an apocalyptic number.
11014104432307 is a deficient number, since it is larger than the sum of its proper divisors (1).
11014104432307 is an equidigital number, since it uses as much as digits as its factorization.
11014104432307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 11014104432307 its reverse (70323440141011), we get a palindrome (81337544573318).
The spelling of 11014104432307 in words is "eleven trillion, fourteen billion, one hundred four million, four hundred thirty-two thousand, three hundred seven".
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