Base | Representation |
---|---|
bin | 1010000001000110110100… |
… | …0010100000010010110011 |
3 | 1102222221101100022110000201 |
4 | 2200101231002200102303 |
5 | 2420423412113120201 |
6 | 35231452554300031 |
7 | 2214513204133453 |
oct | 240215502402263 |
9 | 42887340273021 |
10 | 11014125520051 |
11 | 356707879a225 |
12 | 129a740427617 |
13 | 61b820a40544 |
14 | 2a112d5a3d63 |
15 | 141781833801 |
hex | a046d0a04b3 |
11014125520051 has 2 divisors, whose sum is σ = 11014125520052. Its totient is φ = 11014125520050.
The previous prime is 11014125520019. The next prime is 11014125520121. The reversal of 11014125520051 is 15002552141011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11014125520051 - 25 = 11014125520019 is a prime.
It is a super-2 number, since 2×110141255200512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11014125520351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507062760025 + 5507062760026.
It is an arithmetic number, because the mean of its divisors is an integer number (5507062760026).
Almost surely, 211014125520051 is an apocalyptic number.
11014125520051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11014125520051 is an equidigital number, since it uses as much as digits as its factorization.
11014125520051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2000, while the sum is 28.
Adding to 11014125520051 its reverse (15002552141011), we get a palindrome (26016677661062).
The spelling of 11014125520051 in words is "eleven trillion, fourteen billion, one hundred twenty-five million, five hundred twenty thousand, fifty-one".
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