Base | Representation |
---|---|
bin | 1010000001000110111000… |
… | …0110010111110100101001 |
3 | 1102222221102120210022211010 |
4 | 2200101232012113310221 |
5 | 2420423431141424040 |
6 | 35231454431454133 |
7 | 2214513511302522 |
oct | 240215606276451 |
9 | 42887376708733 |
10 | 11014143311145 |
11 | 3567087840a07 |
12 | 129a746387349 |
13 | 61b82462c410 |
14 | 2a1131ab5849 |
15 | 141783199e80 |
hex | a046e197d29 |
11014143311145 has 64 divisors (see below), whose sum is σ = 19053663148800. Its totient is φ = 5400808123392.
The previous prime is 11014143311137. The next prime is 11014143311179. The reversal of 11014143311145 is 54111334141011.
It is not a de Polignac number, because 11014143311145 - 23 = 11014143311137 is a prime.
It is a super-2 number, since 2×110141433111452 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 128703831 + ... + 128789379.
It is an arithmetic number, because the mean of its divisors is an integer number (297713486700).
Almost surely, 211014143311145 is an apocalyptic number.
11014143311145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11014143311145 is a deficient number, since it is larger than the sum of its proper divisors (8039519837655).
11014143311145 is a wasteful number, since it uses less digits than its factorization.
11014143311145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88186.
The product of its (nonzero) digits is 2880, while the sum is 30.
Adding to 11014143311145 its reverse (54111334141011), we get a palindrome (65125477452156).
The spelling of 11014143311145 in words is "eleven trillion, fourteen billion, one hundred forty-three million, three hundred eleven thousand, one hundred forty-five".
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