Base | Representation |
---|---|
bin | 1010000001000111000111… |
… | …0010100000001010111011 |
3 | 1102222221120220021011220022 |
4 | 2200101301302200022323 |
5 | 2420424043013230243 |
6 | 35231504522321055 |
7 | 2214515162402516 |
oct | 240216162401273 |
9 | 42887526234808 |
10 | 11014205211323 |
11 | 356710977a486 |
12 | 129a76305918b |
13 | 61b8343c3242 |
14 | 2a1139dc9d7d |
15 | 141788825b68 |
hex | a0471ca02bb |
11014205211323 has 2 divisors, whose sum is σ = 11014205211324. Its totient is φ = 11014205211322.
The previous prime is 11014205211313. The next prime is 11014205211343. The reversal of 11014205211323 is 32311250241011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11014205211323 - 210 = 11014205210299 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11014205211292 and 11014205211301.
It is not a weakly prime, because it can be changed into another prime (11014205211313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507102605661 + 5507102605662.
It is an arithmetic number, because the mean of its divisors is an integer number (5507102605662).
Almost surely, 211014205211323 is an apocalyptic number.
11014205211323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11014205211323 is an equidigital number, since it uses as much as digits as its factorization.
11014205211323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 11014205211323 its reverse (32311250241011), we get a palindrome (43325455452334).
The spelling of 11014205211323 in words is "eleven trillion, fourteen billion, two hundred five million, two hundred eleven thousand, three hundred twenty-three".
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