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11014205211323 is a prime number
BaseRepresentation
bin1010000001000111000111…
…0010100000001010111011
31102222221120220021011220022
42200101301302200022323
52420424043013230243
635231504522321055
72214515162402516
oct240216162401273
942887526234808
1011014205211323
11356710977a486
12129a76305918b
1361b8343c3242
142a1139dc9d7d
15141788825b68
hexa0471ca02bb

11014205211323 has 2 divisors, whose sum is σ = 11014205211324. Its totient is φ = 11014205211322.

The previous prime is 11014205211313. The next prime is 11014205211343. The reversal of 11014205211323 is 32311250241011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11014205211323 - 210 = 11014205210299 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11014205211292 and 11014205211301.

It is not a weakly prime, because it can be changed into another prime (11014205211313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507102605661 + 5507102605662.

It is an arithmetic number, because the mean of its divisors is an integer number (5507102605662).

Almost surely, 211014205211323 is an apocalyptic number.

11014205211323 is a deficient number, since it is larger than the sum of its proper divisors (1).

11014205211323 is an equidigital number, since it uses as much as digits as its factorization.

11014205211323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 11014205211323 its reverse (32311250241011), we get a palindrome (43325455452334).

The spelling of 11014205211323 in words is "eleven trillion, fourteen billion, two hundred five million, two hundred eleven thousand, three hundred twenty-three".