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11014339993 is a prime number
BaseRepresentation
bin10100100001000000…
…10111110110011001
31001102121102110000021
422100200113312121
5140024132334433
65020535310441
7536642226256
oct122040276631
931377373007
1011014339993
114742342728
12217481b421
131066ba8757
14766b6442d
15446e7322d
hex290817d99

11014339993 has 2 divisors, whose sum is σ = 11014339994. Its totient is φ = 11014339992.

The previous prime is 11014339951. The next prime is 11014340023. The reversal of 11014339993 is 39993341011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10308747024 + 705592969 = 101532^2 + 26563^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11014339993 is a prime.

It is not a weakly prime, because it can be changed into another prime (11014439993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507169996 + 5507169997.

It is an arithmetic number, because the mean of its divisors is an integer number (5507169997).

Almost surely, 211014339993 is an apocalyptic number.

It is an amenable number.

11014339993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11014339993 is an equidigital number, since it uses as much as digits as its factorization.

11014339993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 78732, while the sum is 43.

The spelling of 11014339993 in words is "eleven billion, fourteen million, three hundred thirty-nine thousand, nine hundred ninety-three".