Base | Representation |
---|---|
bin | 10100100001000001… |
… | …01110111000100111 |
3 | 1001102121121020102201 |
4 | 22100200232320213 |
5 | 140024143344333 |
6 | 5020541315331 |
7 | 536643101323 |
oct | 122040567047 |
9 | 31377536381 |
10 | 11014434343 |
11 | 47423a7600 |
12 | 2174865b47 |
13 | 1066c0c693 |
14 | 766b8a983 |
15 | 446e9117d |
hex | 29082ee27 |
11014434343 has 6 divisors (see below), whose sum is σ = 12106775072. Its totient is φ = 10013122020.
The previous prime is 11014434341. The next prime is 11014434367. The reversal of 11014434343 is 34343441011.
It is a happy number.
It is not a de Polignac number, because 11014434343 - 21 = 11014434341 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11014434341) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 45514071 + ... + 45514312.
Almost surely, 211014434343 is an apocalyptic number.
11014434343 is a deficient number, since it is larger than the sum of its proper divisors (1092340729).
11014434343 is an equidigital number, since it uses as much as digits as its factorization.
11014434343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91028405 (or 91028394 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 11014434343 its reverse (34343441011), we get a palindrome (45357875354).
The spelling of 11014434343 in words is "eleven billion, fourteen million, four hundred thirty-four thousand, three hundred forty-three".
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