Base | Representation |
---|---|
bin | 11001000010110011111111… |
… | …001110111011000001100011 |
3 | 112102222201000020201201110021 |
4 | 121002303333032323001203 |
5 | 103414101234400043413 |
6 | 1030131352151214311 |
7 | 32125446330513025 |
oct | 3102637716730143 |
9 | 472881006651407 |
10 | 110144423440483 |
11 | 32105a95633673 |
12 | 1042a888677397 |
13 | 495c761412853 |
14 | 1d2b038c2a015 |
15 | cb019894d18d |
hex | 642cff3bb063 |
110144423440483 has 2 divisors, whose sum is σ = 110144423440484. Its totient is φ = 110144423440482.
The previous prime is 110144423440421. The next prime is 110144423440507. The reversal of 110144423440483 is 384044324441011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110144423440483 - 221 = 110144421343331 is a prime.
It is not a weakly prime, because it can be changed into another prime (110144423440283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55072211720241 + 55072211720242.
It is an arithmetic number, because the mean of its divisors is an integer number (55072211720242).
Almost surely, 2110144423440483 is an apocalyptic number.
110144423440483 is a deficient number, since it is larger than the sum of its proper divisors (1).
110144423440483 is an equidigital number, since it uses as much as digits as its factorization.
110144423440483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 589824, while the sum is 43.
Adding to 110144423440483 its reverse (384044324441011), we get a palindrome (494188747881494).
The spelling of 110144423440483 in words is "one hundred ten trillion, one hundred forty-four billion, four hundred twenty-three million, four hundred forty thousand, four hundred eighty-three".
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