Base | Representation |
---|---|
bin | 1010000001001010000101… |
… | …1101100100011001010011 |
3 | 1110000000122122021011211012 |
4 | 2200102201131210121103 |
5 | 2420432212241424341 |
6 | 35232120133241135 |
7 | 2214544043632355 |
oct | 240224135443123 |
9 | 43000578234735 |
10 | 11015005029971 |
11 | 356748a1a7028 |
12 | 129a946a931ab |
13 | 61b931011707 |
14 | 2a11b43090d5 |
15 | 1417d3b640eb |
hex | a04a1764653 |
11015005029971 has 2 divisors, whose sum is σ = 11015005029972. Its totient is φ = 11015005029970.
The previous prime is 11015005029949. The next prime is 11015005030019. The reversal of 11015005029971 is 17992050051011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11015005029971 - 26 = 11015005029907 is a prime.
It is not a weakly prime, because it can be changed into another prime (11015005029071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507502514985 + 5507502514986.
It is an arithmetic number, because the mean of its divisors is an integer number (5507502514986).
Almost surely, 211015005029971 is an apocalyptic number.
11015005029971 is a deficient number, since it is larger than the sum of its proper divisors (1).
11015005029971 is an equidigital number, since it uses as much as digits as its factorization.
11015005029971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28350, while the sum is 41.
The spelling of 11015005029971 in words is "eleven trillion, fifteen billion, five million, twenty-nine thousand, nine hundred seventy-one".
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