Base | Representation |
---|---|
bin | 110011010010110010… |
… | …1110001000000111011 |
3 | 101112022201000210102112 |
4 | 1212211211301000323 |
5 | 3301042443320011 |
6 | 122334150322535 |
7 | 10646451204134 |
oct | 1464545610073 |
9 | 345281023375 |
10 | 110152323131 |
11 | 427961297a4 |
12 | 1942195944b |
13 | a505c30336 |
14 | 548d514c8b |
15 | 2cea68558b |
hex | 19a597103b |
110152323131 has 2 divisors, whose sum is σ = 110152323132. Its totient is φ = 110152323130.
The previous prime is 110152323067. The next prime is 110152323137. The reversal of 110152323131 is 131323251011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110152323131 - 26 = 110152323067 is a prime.
It is a super-2 number, since 2×1101523231312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110152323097 and 110152323106.
It is not a weakly prime, because it can be changed into another prime (110152323137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55076161565 + 55076161566.
It is an arithmetic number, because the mean of its divisors is an integer number (55076161566).
Almost surely, 2110152323131 is an apocalyptic number.
110152323131 is a deficient number, since it is larger than the sum of its proper divisors (1).
110152323131 is an equidigital number, since it uses as much as digits as its factorization.
110152323131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 110152323131 its reverse (131323251011), we get a palindrome (241475574142).
The spelling of 110152323131 in words is "one hundred ten billion, one hundred fifty-two million, three hundred twenty-three thousand, one hundred thirty-one".
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