11015400044141 has 4 divisors (see below), whose sum is σ = 11015475756384. Its totient is φ = 11015324331900.

The previous prime is 11015400044137. The next prime is 11015400044227. The reversal of 11015400044141 is 14144000451011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11015400044141 - 2² = 11015400044137 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11015400044141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11015400044111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37637465 + ... + 37929006.

It is an arithmetic number, because the mean of its divisors is an integer number (2753868939096).

Almost surely, 2^{11015400044141} is an apocalyptic number.

It is an amenable number.

11015400044141 is a deficient number, since it is larger than the sum of its proper divisors (75712243).

11015400044141 is an equidigital number, since it uses as much as digits as its factorization.

11015400044141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75712242.

The product of its (nonzero) digits is 1280, while the sum is 26.

Adding to 11015400044141 its reverse (14144000451011), we get a palindrome (25159400495152).

The spelling of 11015400044141 in words is "eleven trillion, fifteen billion, four hundred million, forty-four thousand, one hundred forty-one".