Base | Representation |
---|---|
bin | 10100100001001101… |
… | …01101001010000011 |
3 | 1001102201112210021212 |
4 | 22100212231022003 |
5 | 140030044001011 |
6 | 5021035040335 |
7 | 536662312313 |
oct | 122046551203 |
9 | 31381483255 |
10 | 11016000131 |
11 | 4743276a44 |
12 | 21752a00ab |
13 | 106733a296 |
14 | 767077443 |
15 | 4471a008b |
hex | 2909ad283 |
11016000131 has 2 divisors, whose sum is σ = 11016000132. Its totient is φ = 11016000130.
The previous prime is 11016000049. The next prime is 11016000143. The reversal of 11016000131 is 13100061011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11016000131 - 218 = 11015737987 is a prime.
It is a super-2 number, since 2×110160001312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11016000161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5508000065 + 5508000066.
It is an arithmetic number, because the mean of its divisors is an integer number (5508000066).
Almost surely, 211016000131 is an apocalyptic number.
11016000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11016000131 is an equidigital number, since it uses as much as digits as its factorization.
11016000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 11016000131 its reverse (13100061011), we get a palindrome (24116061142).
The spelling of 11016000131 in words is "eleven billion, sixteen million, one hundred thirty-one", and thus it is an aban number.
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