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11016136453 = 71573733779
BaseRepresentation
bin10100100001001110…
…01110011100000101
31001102201210201021211
422100213032130011
5140030112331303
65021042011421
7536663420620
oct122047163405
931381721254
1011016136453
11474335a403
122175346b71
13106738734a
147670b0db7
154471ca66d
hex2909ce705

11016136453 has 4 divisors (see below), whose sum is σ = 12589870240. Its totient is φ = 9442402668.

The previous prime is 11016136451. The next prime is 11016136487. The reversal of 11016136453 is 35463161011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11016136453 - 21 = 11016136451 is a prime.

It is a super-2 number, since 2×110161364532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11016136451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786866883 + ... + 786866896.

It is an arithmetic number, because the mean of its divisors is an integer number (3147467560).

Almost surely, 211016136453 is an apocalyptic number.

It is an amenable number.

11016136453 is a deficient number, since it is larger than the sum of its proper divisors (1573733787).

11016136453 is an equidigital number, since it uses as much as digits as its factorization.

11016136453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1573733786.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 11016136453 its reverse (35463161011), we get a palindrome (46479297464).

The spelling of 11016136453 in words is "eleven billion, sixteen million, one hundred thirty-six thousand, four hundred fifty-three".

Divisors: 1 7 1573733779 11016136453