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11019735511153 is a prime number
BaseRepresentation
bin1010000001011011101101…
…1010111011000001110001
31110000110212022111112001221
42200112323122323001301
52421021404242324103
635234221400025041
72215102214231605
oct240267332730161
943013768445057
1011019735511153
113569497459606
12129b847162181
1361c2060854c5
142a150268d505
151419ae0cd1bd
hexa05bb6bb071

11019735511153 has 2 divisors, whose sum is σ = 11019735511154. Its totient is φ = 11019735511152.

The previous prime is 11019735511121. The next prime is 11019735511163. The reversal of 11019735511153 is 35111553791011.

11019735511153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6166143181584 + 4853592329569 = 2483172^2 + 2203087^2 .

It is a cyclic number.

It is not a de Polignac number, because 11019735511153 - 25 = 11019735511121 is a prime.

It is not a weakly prime, because it can be changed into another prime (11019735511163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5509867755576 + 5509867755577.

It is an arithmetic number, because the mean of its divisors is an integer number (5509867755577).

Almost surely, 211019735511153 is an apocalyptic number.

It is an amenable number.

11019735511153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11019735511153 is an equidigital number, since it uses as much as digits as its factorization.

11019735511153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 70875, while the sum is 43.

The spelling of 11019735511153 in words is "eleven trillion, nineteen billion, seven hundred thirty-five million, five hundred eleven thousand, one hundred fifty-three".