Base | Representation |
---|---|
bin | 1010000001011101000101… |
… | …0101001111110001100011 |
3 | 1110000111210221020002101012 |
4 | 2200113101111033301203 |
5 | 2421023132344401034 |
6 | 35234322051131135 |
7 | 2215114266664445 |
oct | 240272125176143 |
9 | 43014727202335 |
10 | 11020103122019 |
11 | 3569665a12042 |
12 | 129b92a2a3aab |
13 | 61c264296524 |
14 | 2a1539422495 |
15 | 1419d14e4cce |
hex | a05d154fc63 |
11020103122019 has 2 divisors, whose sum is σ = 11020103122020. Its totient is φ = 11020103122018.
The previous prime is 11020103122013. The next prime is 11020103122031. The reversal of 11020103122019 is 91022130102011.
It is a weak prime.
It is an emirp because it is prime and its reverse (91022130102011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11020103122019 is a prime.
It is a super-3 number, since 3×110201031220193 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 11020103121985 and 11020103122003.
It is not a weakly prime, because it can be changed into another prime (11020103122013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510051561009 + 5510051561010.
It is an arithmetic number, because the mean of its divisors is an integer number (5510051561010).
Almost surely, 211020103122019 is an apocalyptic number.
11020103122019 is a deficient number, since it is larger than the sum of its proper divisors (1).
11020103122019 is an equidigital number, since it uses as much as digits as its factorization.
11020103122019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 11020103122019 in words is "eleven trillion, twenty billion, one hundred three million, one hundred twenty-two thousand, nineteen".
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