Base | Representation |
---|---|
bin | 110011010100010000… |
… | …0101001001100110011 |
3 | 101112110010012200120222 |
4 | 1212220200221030303 |
5 | 3301143013441201 |
6 | 122343100323255 |
7 | 10650614461025 |
oct | 1465040511463 |
9 | 345403180528 |
10 | 110201312051 |
11 | 42810849906 |
12 | 1943624352b |
13 | a51312346c |
14 | 5495c28015 |
15 | 2ceeb1091b |
hex | 19a8829333 |
110201312051 has 2 divisors, whose sum is σ = 110201312052. Its totient is φ = 110201312050.
The previous prime is 110201312017. The next prime is 110201312059. The reversal of 110201312051 is 150213102011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110201312051 is a prime.
It is not a weakly prime, because it can be changed into another prime (110201312059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55100656025 + 55100656026.
It is an arithmetic number, because the mean of its divisors is an integer number (55100656026).
Almost surely, 2110201312051 is an apocalyptic number.
110201312051 is a deficient number, since it is larger than the sum of its proper divisors (1).
110201312051 is an equidigital number, since it uses as much as digits as its factorization.
110201312051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 110201312051 its reverse (150213102011), we get a palindrome (260414414062).
The spelling of 110201312051 in words is "one hundred ten billion, two hundred one million, three hundred twelve thousand, fifty-one".
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