Base | Representation |
---|---|
bin | 110011010100100000… |
… | …1110010010101101001 |
3 | 101112110201120002112111 |
4 | 1212221001302111221 |
5 | 3301202230001413 |
6 | 122344010442321 |
7 | 10651051355014 |
oct | 1465101622551 |
9 | 345421502474 |
10 | 110210000233 |
11 | 42815743423 |
12 | 194391333a1 |
13 | a514b75bb8 |
14 | 549704a37b |
15 | 2d00779d3d |
hex | 19a9072569 |
110210000233 has 2 divisors, whose sum is σ = 110210000234. Its totient is φ = 110210000232.
The previous prime is 110210000209. The next prime is 110210000261. The reversal of 110210000233 is 332000012011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 83291691609 + 26918308624 = 288603^2 + 164068^2 .
It is an emirp because it is prime and its reverse (332000012011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110210000233 - 233 = 101620065641 is a prime.
It is not a weakly prime, because it can be changed into another prime (110210000203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55105000116 + 55105000117.
It is an arithmetic number, because the mean of its divisors is an integer number (55105000117).
Almost surely, 2110210000233 is an apocalyptic number.
It is an amenable number.
110210000233 is a deficient number, since it is larger than the sum of its proper divisors (1).
110210000233 is an equidigital number, since it uses as much as digits as its factorization.
110210000233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 110210000233 its reverse (332000012011), we get a palindrome (442210012244).
The spelling of 110210000233 in words is "one hundred ten billion, two hundred ten million, two hundred thirty-three", and thus it is an aban number.
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