Base | Representation |
---|---|
bin | 1010000001100000011011… |
… | …0111001110000001100001 |
3 | 1110000121010112011012110112 |
4 | 2200120012313032001201 |
5 | 2421032002303021233 |
6 | 35234551132341105 |
7 | 2215145453462456 |
oct | 240300667160141 |
9 | 43017115135415 |
10 | 11021001220193 |
11 | 3569a86965538 |
12 | 129bb3b014795 |
13 | 61c378375373 |
14 | 2a15c280582d |
15 | 141a35298048 |
hex | a0606dce061 |
11021001220193 has 2 divisors, whose sum is σ = 11021001220194. Its totient is φ = 11021001220192.
The previous prime is 11021001220013. The next prime is 11021001220199. The reversal of 11021001220193 is 39102210012011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9850759742464 + 1170241477729 = 3138592^2 + 1081777^2 .
It is a cyclic number.
It is not a de Polignac number, because 11021001220193 - 232 = 11016706252897 is a prime.
It is not a weakly prime, because it can be changed into another prime (11021001220199) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510500610096 + 5510500610097.
It is an arithmetic number, because the mean of its divisors is an integer number (5510500610097).
Almost surely, 211021001220193 is an apocalyptic number.
It is an amenable number.
11021001220193 is a deficient number, since it is larger than the sum of its proper divisors (1).
11021001220193 is an equidigital number, since it uses as much as digits as its factorization.
11021001220193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 11021001220193 in words is "eleven trillion, twenty-one billion, one million, two hundred twenty thousand, one hundred ninety-three".
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