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110211202112222 = 255105601056111
BaseRepresentation
bin11001000011110010001011…
…100011010101101011011110
3112110020002101011120201200202
4121003302023203111223132
5103421200020220042342
61030222154410023502
732133332221042061
oct3103621343255336
9473202334521622
10110211202112222
1132131343435082
121043b804717b92
134965b443617b3
141d30371aa48d8
15cb1ca634b332
hex643c8b8d5ade

110211202112222 has 4 divisors (see below), whose sum is σ = 165316803168336. Its totient is φ = 55105601056110.

The previous prime is 110211202112191. The next prime is 110211202112239. The reversal of 110211202112222 is 222211202112011.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 110211202112194 and 110211202112203.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27552800528054 + ... + 27552800528057.

It is an arithmetic number, because the mean of its divisors is an integer number (41329200792084).

Almost surely, 2110211202112222 is an apocalyptic number.

110211202112222 is a deficient number, since it is larger than the sum of its proper divisors (55105601056114).

110211202112222 is an equidigital number, since it uses as much as digits as its factorization.

110211202112222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55105601056113.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 110211202112222 its reverse (222211202112011), we get a palindrome (332422404224233).

The spelling of 110211202112222 in words is "one hundred ten trillion, two hundred eleven billion, two hundred two million, one hundred twelve thousand, two hundred twenty-two".

Divisors: 1 2 55105601056111 110211202112222