Base | Representation |
---|---|
bin | 1010000001100001001101… |
… | …0100011101011011001011 |
3 | 1110000121200002102002101102 |
4 | 2200120103110131123023 |
5 | 2421032414303241133 |
6 | 35235024000012015 |
7 | 2215153602050243 |
oct | 240302324353313 |
9 | 43017602362342 |
10 | 11021210212043 |
11 | 356a08392a179 |
12 | 129bb9900100b |
13 | 61c3ac75a395 |
14 | 2a1602488b23 |
15 | 141a487cb7e8 |
hex | a061351d6cb |
11021210212043 has 2 divisors, whose sum is σ = 11021210212044. Its totient is φ = 11021210212042.
The previous prime is 11021210211989. The next prime is 11021210212109. The reversal of 11021210212043 is 34021201212011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11021210212043 - 28 = 11021210211787 is a prime.
It is a super-4 number, since 4×110212102120434 (a number of 53 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (11021210212643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510605106021 + 5510605106022.
It is an arithmetic number, because the mean of its divisors is an integer number (5510605106022).
Almost surely, 211021210212043 is an apocalyptic number.
11021210212043 is a deficient number, since it is larger than the sum of its proper divisors (1).
11021210212043 is an equidigital number, since it uses as much as digits as its factorization.
11021210212043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 11021210212043 its reverse (34021201212011), we get a palindrome (45042411424054).
The spelling of 11021210212043 in words is "eleven trillion, twenty-one billion, two hundred ten million, two hundred twelve thousand, forty-three".
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