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11021433130 = 255483201011
BaseRepresentation
bin10100100001110110…
…11011100100101010
31001110002202210222001
422100323123210222
5140032441330010
65021351321214
7540056431051
oct122073334452
931402683861
1011021433130
114746347924
12217708020a
1310684c0186
14767a8d398
154478c4c3a
hex290edb92a

11021433130 has 16 divisors (see below), whose sum is σ = 19842296544. Its totient is φ = 4407747280.

The previous prime is 11021433107. The next prime is 11021433139. The reversal of 11021433130 is 3133412011.

11021433130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 11021433098 and 11021433107.

It is not an unprimeable number, because it can be changed into a prime (11021433139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45676 + ... + 155335.

It is an arithmetic number, because the mean of its divisors is an integer number (1240143534).

Almost surely, 211021433130 is an apocalyptic number.

11021433130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11021433130 is a deficient number, since it is larger than the sum of its proper divisors (8820863414).

11021433130 is a wasteful number, since it uses less digits than its factorization.

11021433130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 206501.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11021433130 its reverse (3133412011), we get a palindrome (14154845141).

The spelling of 11021433130 in words is "eleven billion, twenty-one million, four hundred thirty-three thousand, one hundred thirty".

Divisors: 1 2 5 10 5483 10966 27415 54830 201011 402022 1005055 2010110 1102143313 2204286626 5510716565 11021433130