Base | Representation |
---|---|
bin | 110011010100110101… |
… | …1110100111100010011 |
3 | 101112111111022000010002 |
4 | 1212221223310330103 |
5 | 3301213040132242 |
6 | 122345043000215 |
7 | 10651244135252 |
oct | 1465153647423 |
9 | 345444260102 |
10 | 110221020947 |
11 | 42820990454 |
12 | 1944096906b |
13 | a51723422b |
14 | 54986b8799 |
15 | 2d01705432 |
hex | 19a9af4f13 |
110221020947 has 2 divisors, whose sum is σ = 110221020948. Its totient is φ = 110221020946.
The previous prime is 110221020919. The next prime is 110221020979. The reversal of 110221020947 is 749020122011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110221020947 is a prime.
It is not a weakly prime, because it can be changed into another prime (110221020047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55110510473 + 55110510474.
It is an arithmetic number, because the mean of its divisors is an integer number (55110510474).
Almost surely, 2110221020947 is an apocalyptic number.
110221020947 is a deficient number, since it is larger than the sum of its proper divisors (1).
110221020947 is an equidigital number, since it uses as much as digits as its factorization.
110221020947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 29.
Adding to 110221020947 its reverse (749020122011), we get a palindrome (859241142958).
The spelling of 110221020947 in words is "one hundred ten billion, two hundred twenty-one million, twenty thousand, nine hundred forty-seven".
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