Base | Representation |
---|---|
bin | 10100100010000010… |
… | …11010001101010011 |
3 | 1001110012201102212012 |
4 | 22101001122031103 |
5 | 140033342003103 |
6 | 5021445053135 |
7 | 540105646262 |
oct | 122101321523 |
9 | 31405642765 |
10 | 11023000403 |
11 | 4747218398 |
12 | 21776b71ab |
13 | 106891b65c |
14 | 767d7a5d9 |
15 | 447ad42d8 |
hex | 29105a353 |
11023000403 has 2 divisors, whose sum is σ = 11023000404. Its totient is φ = 11023000402.
The previous prime is 11023000397. The next prime is 11023000441. The reversal of 11023000403 is 30400032011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11023000403 - 28 = 11023000147 is a prime.
It is not a weakly prime, because it can be changed into another prime (11023000103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511500201 + 5511500202.
It is an arithmetic number, because the mean of its divisors is an integer number (5511500202).
Almost surely, 211023000403 is an apocalyptic number.
11023000403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11023000403 is an equidigital number, since it uses as much as digits as its factorization.
11023000403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 11023000403 its reverse (30400032011), we get a palindrome (41423032414).
The spelling of 11023000403 in words is "eleven billion, twenty-three million, four hundred three", and thus it is an aban number.
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