Base | Representation |
---|---|
bin | 1010000001100111111010… |
… | …1110111011000001100100 |
3 | 1110000210022200101012121102 |
4 | 2200121332232323001210 |
5 | 2421100112122424030 |
6 | 35235522453135232 |
7 | 2215246343456414 |
oct | 240317656730144 |
9 | 43023280335542 |
10 | 11023012311140 |
11 | 356a919097975 |
12 | 12a040062a518 |
13 | 61c608c039cb |
14 | 2a173394a644 |
15 | 141b01aebc45 |
hex | a067ebbb064 |
11023012311140 has 12 divisors (see below), whose sum is σ = 23148325853436. Its totient is φ = 4409204924448.
The previous prime is 11023012311107. The next prime is 11023012311173. The reversal of 11023012311140 is 4111321032011.
11023012311140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (11023012311107) and next prime (11023012311173).
It can be written as a sum of positive squares in 2 ways, for example, as 7679848732516 + 3343163578624 = 2771254^2 + 1828432^2 .
It is a Harshad number since it is a multiple of its sum of digits (20), and also a Moran number because the ratio is a prime number: 551150615557 = 11023012311140 / (1 + 1 + 0 + 2 + 3 + 0 + 1 + 2 + 3 + 1 + 1 + 1 + 4 + 0).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 275575307759 + ... + 275575307798.
It is an arithmetic number, because the mean of its divisors is an integer number (1929027154453).
Almost surely, 211023012311140 is an apocalyptic number.
11023012311140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11023012311140 is an abundant number, since it is smaller than the sum of its proper divisors (12125313542296).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11023012311140 is a wasteful number, since it uses less digits than its factorization.
11023012311140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 551150615566 (or 551150615564 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11023012311140 its reverse (4111321032011), we get a palindrome (15134333343151).
The spelling of 11023012311140 in words is "eleven trillion, twenty-three billion, twelve million, three hundred eleven thousand, one hundred forty".
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