Base | Representation |
---|---|
bin | 10000000010100110011… |
… | …100000101111110010011 |
3 | 10220101020110110121110022 |
4 | 100002212130011332103 |
5 | 121030004311311011 |
6 | 2202220320254055 |
7 | 142432056330152 |
oct | 20024634057623 |
9 | 3811213417408 |
10 | 1102304010131 |
11 | 3955369709a5 |
12 | 15977347132b |
13 | 7cc4022578c |
14 | 3b4cd49b599 |
15 | 1da17db58db |
hex | 100a6705f93 |
1102304010131 has 2 divisors, whose sum is σ = 1102304010132. Its totient is φ = 1102304010130.
The previous prime is 1102304010121. The next prime is 1102304010139. The reversal of 1102304010131 is 1310104032011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1102304010131 is a prime.
It is a super-2 number, since 2×11023040101312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1102304010139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551152005065 + 551152005066.
It is an arithmetic number, because the mean of its divisors is an integer number (551152005066).
Almost surely, 21102304010131 is an apocalyptic number.
1102304010131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102304010131 is an equidigital number, since it uses as much as digits as its factorization.
1102304010131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1102304010131 its reverse (1310104032011), we get a palindrome (2412408042142).
The spelling of 1102304010131 in words is "one trillion, one hundred two billion, three hundred four million, ten thousand, one hundred thirty-one".
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