Base | Representation |
---|---|
bin | 11001000100000100111001… |
… | …101010101001001100000011 |
3 | 112110022000021001012022220022 |
4 | 121010010321222221030003 |
5 | 103422012202100210112 |
6 | 1030235321144404055 |
7 | 32134643310636026 |
oct | 3104047152511403 |
9 | 473260231168808 |
10 | 110231303131907 |
11 | 32139918991741 |
12 | 1044369447662b |
13 | 49679c8949099 |
14 | 1d3131b5651bd |
15 | cb2580dbdd72 |
hex | 644139aa9303 |
110231303131907 has 2 divisors, whose sum is σ = 110231303131908. Its totient is φ = 110231303131906.
The previous prime is 110231303131879. The next prime is 110231303131913. The reversal of 110231303131907 is 709131303132011.
It is a strong prime.
It is an emirp because it is prime and its reverse (709131303132011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110231303131907 - 228 = 110231034696451 is a prime.
It is not a weakly prime, because it can be changed into another prime (110231303131987) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55115651565953 + 55115651565954.
It is an arithmetic number, because the mean of its divisors is an integer number (55115651565954).
Almost surely, 2110231303131907 is an apocalyptic number.
110231303131907 is a deficient number, since it is larger than the sum of its proper divisors (1).
110231303131907 is an equidigital number, since it uses as much as digits as its factorization.
110231303131907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10206, while the sum is 35.
Adding to 110231303131907 its reverse (709131303132011), we get a palindrome (819362606263918).
The spelling of 110231303131907 in words is "one hundred ten trillion, two hundred thirty-one billion, three hundred three million, one hundred thirty-one thousand, nine hundred seven".
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