1102333131133 has 4 divisors (see below), whose sum is σ = 1187127987388. Its totient is φ = 1017538274880.

The previous prime is 1102333131113. The next prime is 1102333131169. The reversal of 1102333131133 is 3311313332011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 635971160484 + 466361970649 = 797478^2 + 682907^2 .

It is a cyclic number.

It is not a de Polignac number, because 1102333131133 - 2⁹ = 1102333130621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1102333131098 and 1102333131107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1102333131113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42397428108 + ... + 42397428133.

It is an arithmetic number, because the mean of its divisors is an integer number (296781996847).

Almost surely, 2^{1102333131133} is an apocalyptic number.

1102333131133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1102333131133 is a deficient number, since it is larger than the sum of its proper divisors (84794856255).

1102333131133 is an equidigital number, since it uses as much as digits as its factorization.

1102333131133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84794856254.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1102333131133 its reverse (3311313332011), we get a palindrome (4413646463144).

The spelling of 1102333131133 in words is "one trillion, one hundred two billion, three hundred thirty-three million, one hundred thirty-one thousand, one hundred thirty-three".