Base | Representation |
---|---|
bin | 1010000001101001100001… |
… | …1110001001110000010001 |
3 | 1110000211102202220111121222 |
4 | 2200122120132021300101 |
5 | 2421102003143411031 |
6 | 35240033400254425 |
7 | 2215263136013156 |
oct | 240323036116021 |
9 | 43024382814558 |
10 | 11023444122641 |
11 | 357001a910285 |
12 | 12a0501171415 |
13 | 61c677502982 |
14 | 2a177503222d |
15 | 141b29995e7b |
hex | a0698789c11 |
11023444122641 has 2 divisors, whose sum is σ = 11023444122642. Its totient is φ = 11023444122640.
The previous prime is 11023444122637. The next prime is 11023444122661. The reversal of 11023444122641 is 14622144432011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10374815232016 + 648628890625 = 3220996^2 + 805375^2 .
It is a cyclic number.
It is not a de Polignac number, because 11023444122641 - 22 = 11023444122637 is a prime.
It is not a weakly prime, because it can be changed into another prime (11023444122601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511722061320 + 5511722061321.
It is an arithmetic number, because the mean of its divisors is an integer number (5511722061321).
Almost surely, 211023444122641 is an apocalyptic number.
It is an amenable number.
11023444122641 is a deficient number, since it is larger than the sum of its proper divisors (1).
11023444122641 is an equidigital number, since it uses as much as digits as its factorization.
11023444122641 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36864, while the sum is 35.
Adding to 11023444122641 its reverse (14622144432011), we get a palindrome (25645588554652).
The spelling of 11023444122641 in words is "eleven trillion, twenty-three billion, four hundred forty-four million, one hundred twenty-two thousand, six hundred forty-one".
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