Base | Representation |
---|---|
bin | 10100100010001001… |
… | …11000110111111001 |
3 | 1001110021102202221101 |
4 | 22101010320313321 |
5 | 140034110144231 |
6 | 5021520411401 |
7 | 540116465263 |
oct | 122104706771 |
9 | 31407382841 |
10 | 11023912441 |
11 | 4747790643 |
12 | 2177a76b61 |
13 | 1068b7a819 |
14 | 768136b33 |
15 | 447c14661 |
hex | 291138df9 |
11023912441 has 2 divisors, whose sum is σ = 11023912442. Its totient is φ = 11023912440.
The previous prime is 11023912421. The next prime is 11023912507. The reversal of 11023912441 is 14421932011.
11023912441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8151381225 + 2872531216 = 90285^2 + 53596^2 .
It is a cyclic number.
It is not a de Polignac number, because 11023912441 - 25 = 11023912409 is a prime.
It is not a weakly prime, because it can be changed into another prime (11023912421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511956220 + 5511956221.
It is an arithmetic number, because the mean of its divisors is an integer number (5511956221).
Almost surely, 211023912441 is an apocalyptic number.
It is an amenable number.
11023912441 is a deficient number, since it is larger than the sum of its proper divisors (1).
11023912441 is an equidigital number, since it uses as much as digits as its factorization.
11023912441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 28.
The spelling of 11023912441 in words is "eleven billion, twenty-three million, nine hundred twelve thousand, four hundred forty-one".
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