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1102402341913 is a prime number
BaseRepresentation
bin10000000010101100010…
…011001100110000011001
310220101111022111101022011
4100002230103030300121
5121030204444420123
62202234152025521
7142434362203555
oct20025423146031
93811438441264
101102402341913
11395587423034
121597a03922a1
137cc57703b72
143b4dc576865
151da2183ae0d
hex100ac4ccc19

1102402341913 has 2 divisors, whose sum is σ = 1102402341914. Its totient is φ = 1102402341912.

The previous prime is 1102402341851. The next prime is 1102402341917. The reversal of 1102402341913 is 3191432042011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 824296936464 + 278105405449 = 907908^2 + 527357^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1102402341913 is a prime.

It is not a weakly prime, because it can be changed into another prime (1102402341917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551201170956 + 551201170957.

It is an arithmetic number, because the mean of its divisors is an integer number (551201170957).

Almost surely, 21102402341913 is an apocalyptic number.

It is an amenable number.

1102402341913 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102402341913 is an equidigital number, since it uses as much as digits as its factorization.

1102402341913 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 31.

Adding to 1102402341913 its reverse (3191432042011), we get a palindrome (4293834383924).

The spelling of 1102402341913 in words is "one trillion, one hundred two billion, four hundred two million, three hundred forty-one thousand, nine hundred thirteen".