Base | Representation |
---|---|
bin | 11001000100001101111100… |
… | …011010111011100111011011 |
3 | 112110022221022202001210212201 |
4 | 121010031330122323213123 |
5 | 103422142043313134042 |
6 | 1030244004445151031 |
7 | 32135436033430021 |
oct | 3104157432734733 |
9 | 473287282053781 |
10 | 110241013021147 |
11 | 32142a50967198 |
12 | 1044554425b477 |
13 | 49688b54bba88 |
14 | 1d3199cd6a711 |
15 | cb294d5731b7 |
hex | 64437c6bb9db |
110241013021147 has 2 divisors, whose sum is σ = 110241013021148. Its totient is φ = 110241013021146.
The previous prime is 110241013021091. The next prime is 110241013021213. The reversal of 110241013021147 is 741120310142011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110241013021147 is a prime.
It is not a weakly prime, because it can be changed into another prime (110241013021247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55120506510573 + 55120506510574.
It is an arithmetic number, because the mean of its divisors is an integer number (55120506510574).
Almost surely, 2110241013021147 is an apocalyptic number.
110241013021147 is a deficient number, since it is larger than the sum of its proper divisors (1).
110241013021147 is an equidigital number, since it uses as much as digits as its factorization.
110241013021147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 28.
Adding to 110241013021147 its reverse (741120310142011), we get a palindrome (851361323163158).
The spelling of 110241013021147 in words is "one hundred ten trillion, two hundred forty-one billion, thirteen million, twenty-one thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •