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110241143322041 is a prime number
BaseRepresentation
bin11001000100001110000100…
…001011111111010110111001
3112110022221122211020210002202
4121010032010023333112321
5103422142330142301131
61030244025422035545
732135442205113014
oct3104160413772671
9473287584223082
10110241143322041
1132143008474186
121044557ba18bb5
1349689064b14b4
141d319b23a837b
15cb2959c10bcb
hex6443842ff5b9

110241143322041 has 2 divisors, whose sum is σ = 110241143322042. Its totient is φ = 110241143322040.

The previous prime is 110241143321951. The next prime is 110241143322077. The reversal of 110241143322041 is 140223341142011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109645191745600 + 595951576441 = 10471160^2 + 771979^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110241143322041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110241143321995 and 110241143322013.

It is not a weakly prime, because it can be changed into another prime (110241143321041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55120571661020 + 55120571661021.

It is an arithmetic number, because the mean of its divisors is an integer number (55120571661021).

Almost surely, 2110241143322041 is an apocalyptic number.

It is an amenable number.

110241143322041 is a deficient number, since it is larger than the sum of its proper divisors (1).

110241143322041 is an equidigital number, since it uses as much as digits as its factorization.

110241143322041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 110241143322041 its reverse (140223341142011), we get a palindrome (250464484464052).

The spelling of 110241143322041 in words is "one hundred ten trillion, two hundred forty-one billion, one hundred forty-three million, three hundred twenty-two thousand, forty-one".