Base | Representation |
---|---|
bin | 110011010101100000… |
… | …1010100101011110001 |
3 | 101112120001110122221120 |
4 | 1212223001110223301 |
5 | 3301234304330301 |
6 | 122351203212453 |
7 | 10651635502146 |
oct | 1465301245361 |
9 | 345501418846 |
10 | 110243433201 |
11 | 428325a9080 |
12 | 19448377129 |
13 | a51ba80615 |
14 | 549b6703cd |
15 | 2d03680e36 |
hex | 19ab054af1 |
110243433201 has 16 divisors (see below), whose sum is σ = 160614007488. Its totient is φ = 66705900800.
The previous prime is 110243433193. The next prime is 110243433233. The reversal of 110243433201 is 102334342011.
It is a happy number.
It is not a de Polignac number, because 110243433201 - 23 = 110243433193 is a prime.
It is a super-2 number, since 2×1102434332012 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (110243433101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2686860 + ... + 2727581.
It is an arithmetic number, because the mean of its divisors is an integer number (10038375468).
Almost surely, 2110243433201 is an apocalyptic number.
110243433201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
110243433201 is a deficient number, since it is larger than the sum of its proper divisors (50370574287).
110243433201 is a wasteful number, since it uses less digits than its factorization.
110243433201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5415072.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 110243433201 its reverse (102334342011), we get a palindrome (212577775212).
The spelling of 110243433201 in words is "one hundred ten billion, two hundred forty-three million, four hundred thirty-three thousand, two hundred one".
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