Search a number
-
+
11024445401513 is a prime number
BaseRepresentation
bin1010000001101101010000…
…1001101110100110101001
31110000221000112222202000122
42200123110021232212221
52421111031010322023
635240321005213025
72215330014521435
oct240332411564651
943027015882018
1011024445401513
113570494027985
1212a0740561175
1361c7a6a99c8b
142a182bdd39c5
15141b8782b2c8
hexa06d426e9a9

11024445401513 has 2 divisors, whose sum is σ = 11024445401514. Its totient is φ = 11024445401512.

The previous prime is 11024445401447. The next prime is 11024445401521. The reversal of 11024445401513 is 31510454442011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8627190835264 + 2397254566249 = 2937208^2 + 1548307^2 .

It is a cyclic number.

It is not a de Polignac number, because 11024445401513 - 28 = 11024445401257 is a prime.

It is a super-2 number, since 2×110244454015132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11024445401813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5512222700756 + 5512222700757.

It is an arithmetic number, because the mean of its divisors is an integer number (5512222700757).

Almost surely, 211024445401513 is an apocalyptic number.

It is an amenable number.

11024445401513 is a deficient number, since it is larger than the sum of its proper divisors (1).

11024445401513 is an equidigital number, since it uses as much as digits as its factorization.

11024445401513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38400, while the sum is 35.

Adding to 11024445401513 its reverse (31510454442011), we get a palindrome (42534899843524).

The spelling of 11024445401513 in words is "eleven trillion, twenty-four billion, four hundred forty-five million, four hundred one thousand, five hundred thirteen".