Base | Representation |
---|---|
bin | 10000000010111101000… |
… | …010010100001110110011 |
3 | 10220102012212211211102211 |
4 | 100002331002110032303 |
5 | 121031243340110010 |
6 | 2202322102152551 |
7 | 142444341642235 |
oct | 20027502241663 |
9 | 3812185754384 |
10 | 1102683128755 |
11 | 39571097437a |
12 | 15985a422757 |
13 | 7cca0935720 |
14 | 3b527988255 |
15 | 1da3b30208a |
hex | 100bd0943b3 |
1102683128755 has 32 divisors (see below), whose sum is σ = 1531921305600. Its totient is φ = 755018278272.
The previous prime is 1102683128753. The next prime is 1102683128773. The reversal of 1102683128755 is 5578213862011.
It is a cyclic number.
It is not a de Polignac number, because 1102683128755 - 21 = 1102683128753 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1102683128699 and 1102683128708.
It is not an unprimeable number, because it can be changed into a prime (1102683128753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9440475 + ... + 9556564.
It is an arithmetic number, because the mean of its divisors is an integer number (47872540800).
Almost surely, 21102683128755 is an apocalyptic number.
1102683128755 is a deficient number, since it is larger than the sum of its proper divisors (429238176845).
1102683128755 is a wasteful number, since it uses less digits than its factorization.
1102683128755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18997123.
The product of its (nonzero) digits is 806400, while the sum is 49.
The spelling of 1102683128755 in words is "one trillion, one hundred two billion, six hundred eighty-three million, one hundred twenty-eight thousand, seven hundred fifty-five".
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