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11030002111313 is a prime number
BaseRepresentation
bin1010000010000001111101…
…0110111001001101010001
31110001110100210220211212022
42200200133112321031101
52421203421020030223
635243040224541225
72215614510004523
oct240403726711521
943043323824768
1011030002111313
113572885705229
1212a1831481815
13620181078143
142a1bd7dada13
15141db059dac8
hexa081f5b9351

11030002111313 has 2 divisors, whose sum is σ = 11030002111314. Its totient is φ = 11030002111312.

The previous prime is 11030002111291. The next prime is 11030002111357. The reversal of 11030002111313 is 31311120003011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5589408541249 + 5440593570064 = 2364193^2 + 2332508^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11030002111313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11030002111291 and 11030002111300.

It is not a weakly prime, because it can be changed into another prime (11030002116313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515001055656 + 5515001055657.

It is an arithmetic number, because the mean of its divisors is an integer number (5515001055657).

Almost surely, 211030002111313 is an apocalyptic number.

It is an amenable number.

11030002111313 is a deficient number, since it is larger than the sum of its proper divisors (1).

11030002111313 is an equidigital number, since it uses as much as digits as its factorization.

11030002111313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11030002111313 its reverse (31311120003011), we get a palindrome (42341122114324).

The spelling of 11030002111313 in words is "eleven trillion, thirty billion, two million, one hundred eleven thousand, three hundred thirteen".