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110300232113 is a prime number
BaseRepresentation
bin110011010111001100…
…1111111100110110001
3101112201000100100101222
41212232121333212301
53301343324411423
6122400552434425
710653225334511
oct1465631774661
9345630310358
10110300232113
1142861672a25
12194633a8a15
13a52a779546
1454a5017841
152d086503c8
hex19ae67f9b1

110300232113 has 2 divisors, whose sum is σ = 110300232114. Its totient is φ = 110300232112.

The previous prime is 110300232101. The next prime is 110300232127. The reversal of 110300232113 is 311232003011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 60264358144 + 50035873969 = 245488^2 + 223687^2 .

It is a cyclic number.

It is not a de Polignac number, because 110300232113 - 210 = 110300231089 is a prime.

It is a super-2 number, since 2×1103002321132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110300232091 and 110300232100.

It is not a weakly prime, because it can be changed into another prime (110300232143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55150116056 + 55150116057.

It is an arithmetic number, because the mean of its divisors is an integer number (55150116057).

Almost surely, 2110300232113 is an apocalyptic number.

It is an amenable number.

110300232113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110300232113 is an equidigital number, since it uses as much as digits as its factorization.

110300232113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 110300232113 its reverse (311232003011), we get a palindrome (421532235124).

The spelling of 110300232113 in words is "one hundred ten billion, three hundred million, two hundred thirty-two thousand, one hundred thirteen".