Base | Representation |
---|---|
bin | 1010000010000010011100… |
… | …0011010101011111101111 |
3 | 1110001110200210211100001000 |
4 | 2200200213003111133233 |
5 | 2421204202041431111 |
6 | 35243101115451343 |
7 | 2215620635160354 |
oct | 240404703253757 |
9 | 43043623740030 |
10 | 11030131202031 |
11 | 3572941565a77 |
12 | 12a1868756b53 |
13 | 6201a1a35a96 |
14 | 2a1c0b1b462b |
15 | 141dbba9cc56 |
hex | a08270d57ef |
11030131202031 has 16 divisors (see below), whose sum is σ = 16720956862720. Its totient is φ = 7182411014520.
The previous prime is 11030131202029. The next prime is 11030131202087. The reversal of 11030131202031 is 13020213103011.
11030131202031 is a `hidden beast` number, since 1 + 1 + 0 + 301 + 312 + 0 + 20 + 31 = 666.
11030131202031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11030131202031 - 21 = 11030131202029 is a prime.
It is a super-2 number, since 2×110301312020312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11030131201995 and 11030131202013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11030131202731) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4750270675 + ... + 4750272996.
It is an arithmetic number, because the mean of its divisors is an integer number (1045059803920).
Almost surely, 211030131202031 is an apocalyptic number.
11030131202031 is a deficient number, since it is larger than the sum of its proper divisors (5690825660689).
11030131202031 is an equidigital number, since it uses as much as digits as its factorization.
11030131202031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9500543723 (or 9500543717 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 11030131202031 its reverse (13020213103011), we get a palindrome (24050344305042).
The spelling of 11030131202031 in words is "eleven trillion, thirty billion, one hundred thirty-one million, two hundred two thousand, thirty-one".
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