Base | Representation |
---|---|
bin | 1010000010000101110011… |
… | …0011011101101100111011 |
3 | 1110001120000122201222101022 |
4 | 2200201130303131230323 |
5 | 2421213023422323003 |
6 | 35243330412413055 |
7 | 2215652165342135 |
oct | 240413463355473 |
9 | 43046018658338 |
10 | 11031033011003 |
11 | 3573264613445 |
12 | 12a1a7a77718b |
13 | 6202b6813965 |
14 | 2a1c94c82055 |
15 | 141e20d35738 |
hex | a085ccddb3b |
11031033011003 has 2 divisors, whose sum is σ = 11031033011004. Its totient is φ = 11031033011002.
The previous prime is 11031033010973. The next prime is 11031033011041. The reversal of 11031033011003 is 30011033013011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11031033011003 - 238 = 10756155104059 is a prime.
It is not a weakly prime, because it can be changed into another prime (11031033011203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515516505501 + 5515516505502.
It is an arithmetic number, because the mean of its divisors is an integer number (5515516505502).
Almost surely, 211031033011003 is an apocalyptic number.
11031033011003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11031033011003 is an equidigital number, since it uses as much as digits as its factorization.
11031033011003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 11031033011003 its reverse (30011033013011), we get a palindrome (41042066024014).
The spelling of 11031033011003 in words is "eleven trillion, thirty-one billion, thirty-three million, eleven thousand, three".
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