Base | Representation |
---|---|
bin | 10100100011000000… |
… | …11100000011100001 |
3 | 1001110210000200122120 |
4 | 22101200130003201 |
5 | 140042432300213 |
6 | 5022335254453 |
7 | 540235044534 |
oct | 122140340341 |
9 | 31423020576 |
10 | 11031134433 |
11 | 4750873630 |
12 | 217a37a429 |
13 | 106a508aa7 |
14 | 769096a1b |
15 | 44868e423 |
hex | 29181c0e1 |
11031134433 has 32 divisors (see below), whose sum is σ = 16132405632. Its totient is φ = 6649344000.
The previous prime is 11031134407. The next prime is 11031134503. The reversal of 11031134433 is 33443113011.
It is not a de Polignac number, because 11031134433 - 213 = 11031126241 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11031134033) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6206841 + ... + 6208617.
It is an arithmetic number, because the mean of its divisors is an integer number (504137676).
Almost surely, 211031134433 is an apocalyptic number.
It is an amenable number.
11031134433 is a deficient number, since it is larger than the sum of its proper divisors (5101271199).
11031134433 is a wasteful number, since it uses less digits than its factorization.
11031134433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2705.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 11031134433 its reverse (33443113011), we get a palindrome (44474247444).
The spelling of 11031134433 in words is "eleven billion, thirty-one million, one hundred thirty-four thousand, four hundred thirty-three".
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