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1103131314151 = 17137321472543
BaseRepresentation
bin10000000011010111110…
…000000000011111100111
310220110101010012000012221
4100003113300000133213
5121033203104023101
62202434352253211
7142461423313216
oct20032760003747
93813333160187
101103131314151
11395920960729
12159964541207
1380042748499
143b56b2d307d
151da65832aa1
hex100d7c007e7

1103131314151 has 8 divisors (see below), whose sum is σ = 1168032369024. Its totient is φ = 1038231479040.

The previous prime is 1103131314149. The next prime is 1103131314161. The reversal of 1103131314151 is 1514131313011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1103131314151 - 21 = 1103131314149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1103131314161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2098186 + ... + 2570728.

It is an arithmetic number, because the mean of its divisors is an integer number (146004046128).

Almost surely, 21103131314151 is an apocalyptic number.

1103131314151 is a deficient number, since it is larger than the sum of its proper divisors (64901054873).

1103131314151 is a wasteful number, since it uses less digits than its factorization.

1103131314151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 609881.

The product of its (nonzero) digits is 540, while the sum is 25.

Adding to 1103131314151 its reverse (1514131313011), we get a palindrome (2617262627162).

The spelling of 1103131314151 in words is "one trillion, one hundred three billion, one hundred thirty-one million, three hundred fourteen thousand, one hundred fifty-one".

Divisors: 1 17 137321 472543 2334457 8033231 64890077303 1103131314151