1103134147 has 4 divisors (see below), whose sum is σ = 1103209416. Its totient is φ = 1103058880.

The previous prime is 1103134141. The next prime is 1103134177. The reversal of 1103134147 is 7414313011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 7414313011 = 7 ⋅1059187573.

It is a cyclic number.

It is not a de Polignac number, because 1103134147 - 2¹⁵ = 1103101379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1103134141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7729 + ... + 47602.

It is an arithmetic number, because the mean of its divisors is an integer number (275802354).

Almost surely, 2^1103134147 is an apocalyptic number.

1103134147 is a deficient number, since it is larger than the sum of its proper divisors (75269).

1103134147 is an equidigital number, since it uses as much as digits as its factorization.

1103134147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75268.

The product of its (nonzero) digits is 1008, while the sum is 25.

The square root of 1103134147 is about 33213.4633394351. The cubic root of 1103134147 is about 1033.2595850825.

Adding to 1103134147 its reverse (7414313011), we get a palindrome (8517447158).

The spelling of 1103134147 in words is "one billion, one hundred three million, one hundred thirty-four thousand, one hundred forty-seven".