Base | Representation |
---|---|
bin | 10100100011000111… |
… | …10101000001001001 |
3 | 1001110211200211200122 |
4 | 22101203311001021 |
5 | 140043144214423 |
6 | 5022410313025 |
7 | 540245435456 |
oct | 122143650111 |
9 | 31424624618 |
10 | 11032023113 |
11 | 4751320281 |
12 | 217a728775 |
13 | 106a75a437 |
14 | 76924882d |
15 | 4487b78c8 |
hex | 2918f5049 |
11032023113 has 2 divisors, whose sum is σ = 11032023114. Its totient is φ = 11032023112.
The previous prime is 11032023077. The next prime is 11032023169. The reversal of 11032023113 is 31132023011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7291110544 + 3740912569 = 85388^2 + 61163^2 .
It is an emirp because it is prime and its reverse (31132023011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11032023113 - 214 = 11032006729 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11032023091 and 11032023100.
It is not a weakly prime, because it can be changed into another prime (11032026113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516011556 + 5516011557.
It is an arithmetic number, because the mean of its divisors is an integer number (5516011557).
Almost surely, 211032023113 is an apocalyptic number.
It is an amenable number.
11032023113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11032023113 is an equidigital number, since it uses as much as digits as its factorization.
11032023113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11032023113 its reverse (31132023011), we get a palindrome (42164046124).
The spelling of 11032023113 in words is "eleven billion, thirty-two million, twenty-three thousand, one hundred thirteen".
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