Base | Representation |
---|---|
bin | 1010000010001101100101… |
… | …1100110111111110110111 |
3 | 1110001202102101202111002120 |
4 | 2200203121130313332313 |
5 | 2421231314301210320 |
6 | 35244314115011023 |
7 | 2216055050452440 |
oct | 240433134677667 |
9 | 43052371674076 |
10 | 11033124241335 |
11 | 3574138001779 |
12 | 12a2362b99a73 |
13 | 62055ab50c61 |
14 | 2a20128c82c7 |
15 | 141ee4719440 |
hex | a08d9737fb7 |
11033124241335 has 64 divisors (see below), whose sum is σ = 20390212930560. Its totient is φ = 4990012231680.
The previous prime is 11033124241327. The next prime is 11033124241361. The reversal of 11033124241335 is 53314242133011.
It is not a de Polignac number, because 11033124241335 - 23 = 11033124241327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11033124241296 and 11033124241305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6986280 + ... + 8418690.
It is an arithmetic number, because the mean of its divisors is an integer number (318597077040).
Almost surely, 211033124241335 is an apocalyptic number.
11033124241335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11033124241335 is a deficient number, since it is larger than the sum of its proper divisors (9357088689225).
11033124241335 is a wasteful number, since it uses less digits than its factorization.
11033124241335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1433208.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 11033124241335 its reverse (53314242133011), we get a palindrome (64347366374346).
The spelling of 11033124241335 in words is "eleven trillion, thirty-three billion, one hundred twenty-four million, two hundred forty-one thousand, three hundred thirty-five".
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