Base | Representation |
---|---|
bin | 11001000101100010110001… |
… | …110000010011110110101001 |
3 | 112110122122102220022001000012 |
4 | 121011202301300103312221 |
5 | 103430140121121143423 |
6 | 1030353511253021305 |
7 | 32145142226202212 |
oct | 3105426160236651 |
9 | 473578386261005 |
10 | 110332102131113 |
11 | 32178644334765 |
12 | 1045b125924835 |
13 | 4974370b4b005 |
14 | 1d36160770409 |
15 | cb4ed0334078 |
hex | 6458b1c13da9 |
110332102131113 has 2 divisors, whose sum is σ = 110332102131114. Its totient is φ = 110332102131112.
The previous prime is 110332102131109. The next prime is 110332102131217. The reversal of 110332102131113 is 311131201233011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 97457805573184 + 12874296557929 = 9872072^2 + 3588077^2 .
It is a cyclic number.
It is not a de Polignac number, because 110332102131113 - 22 = 110332102131109 is a prime.
It is not a weakly prime, because it can be changed into another prime (110332102131613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55166051065556 + 55166051065557.
It is an arithmetic number, because the mean of its divisors is an integer number (55166051065557).
Almost surely, 2110332102131113 is an apocalyptic number.
It is an amenable number.
110332102131113 is a deficient number, since it is larger than the sum of its proper divisors (1).
110332102131113 is an equidigital number, since it uses as much as digits as its factorization.
110332102131113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 110332102131113 its reverse (311131201233011), we get a palindrome (421463303364124).
The spelling of 110332102131113 in words is "one hundred ten trillion, three hundred thirty-two billion, one hundred two million, one hundred thirty-one thousand, one hundred thirteen".
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