Base | Representation |
---|---|
bin | 10000000011100011010… |
… | …000101111010101101101 |
3 | 10220110212120121000120210 |
4 | 100003203100233111231 |
5 | 121034102024202023 |
6 | 2202505451533033 |
7 | 142466260015101 |
oct | 20034320572555 |
9 | 3813776530523 |
10 | 1103324444013 |
11 | 395a0a980a90 |
12 | 1599b915a179 |
13 | 800737686cc |
14 | 3b588c07901 |
15 | 1da77781593 |
hex | 100e342f56d |
1103324444013 has 16 divisors (see below), whose sum is σ = 1643977887552. Its totient is φ = 652372176000.
The previous prime is 1103324443999. The next prime is 1103324444051. The reversal of 1103324444013 is 3104444233011.
It is not a de Polignac number, because 1103324444013 - 25 = 1103324443981 is a prime.
It is a super-4 number, since 4×11033244440134 (a number of 49 digits) contains 4444 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1103324444093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 407731258 + ... + 407733963.
It is an arithmetic number, because the mean of its divisors is an integer number (102748617972).
Almost surely, 21103324444013 is an apocalyptic number.
It is an amenable number.
1103324444013 is a deficient number, since it is larger than the sum of its proper divisors (540653443539).
1103324444013 is a wasteful number, since it uses less digits than its factorization.
1103324444013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 815465276.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 1103324444013 its reverse (3104444233011), we get a palindrome (4207768677024).
The spelling of 1103324444013 in words is "one trillion, one hundred three billion, three hundred twenty-four million, four hundred forty-four thousand, thirteen".
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