Base | Representation |
---|---|
bin | 10000000011100011100… |
… | …110010100111101011011 |
3 | 10220110212222020112102202 |
4 | 100003203212110331123 |
5 | 121034110001300011 |
6 | 2202510213120415 |
7 | 142466356065014 |
oct | 20034346247533 |
9 | 3813788215382 |
10 | 1103330103131 |
11 | 395a13096843 |
12 | 1599bb02910b |
13 | 8007499a4b9 |
14 | 3b58987c00b |
15 | 1da77eed23b |
hex | 100e3994f5b |
1103330103131 has 2 divisors, whose sum is σ = 1103330103132. Its totient is φ = 1103330103130.
The previous prime is 1103330103121. The next prime is 1103330103149. The reversal of 1103330103131 is 1313010333011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1103330103131 - 222 = 1103325908827 is a prime.
It is a super-2 number, since 2×11033301031312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1103330103121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551665051565 + 551665051566.
It is an arithmetic number, because the mean of its divisors is an integer number (551665051566).
Almost surely, 21103330103131 is an apocalyptic number.
1103330103131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1103330103131 is an equidigital number, since it uses as much as digits as its factorization.
1103330103131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 1103330103131 its reverse (1313010333011), we get a palindrome (2416340436142).
The spelling of 1103330103131 in words is "one trillion, one hundred three billion, three hundred thirty million, one hundred three thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •